1/2y+42/2y-3=9/4y^2+2y-12

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Solution for 1/2y+42/2y-3=9/4y^2+2y-12 equation: 


y in (-oo:+oo)

(1/2)*y+(42/2)*y-3 = (9/4)*y^2+2*y-12 // - (9/4)*y^2+2*y-12

(1/2)*y-((9/4)*y^2)+(42/2)*y-(2*y)-3+12 = 0

(-9/4)*y^2+(1/2)*y+(42/2)*y-2*y-3+12 = 0

39/2*y-9/4*y^2+9 = 0

DELTA = (39/2)^2-(-9/4*4*9)

DELTA = 1845/4

DELTA > 0

y = ((1845/4)^(1/2)-39/2)/(-9/4*2) or y = (-(1845/4)^(1/2)-39/2)/(-9/4*2)

y = -2/9*((1845/4)^(1/2)-39/2) or y = 2/9*((1845/4)^(1/2)+39/2)

y in { -2/9*((1845/4)^(1/2)-39/2), 2/9*((1845/4)^(1/2)+39/2) }

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